sql; snowflake-cloud-data-platform;. Snowflake separates compute from storage, allowing for flexible pricing and configuration. 141') -- FAILURE: The datediff function resulted in an overflow. datediff(part: str, col1: ColumnOrName, col2: ColumnOrName) → Column [source] Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. 複数の行が評価される場合（例: 入力が複数の行を含むテーブルの列名である場合）、値が秒. datediff (part: str, col1: Column | str, col2: Column | str) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. snowpark. My stored procedure is static, meaning, I address the table X directly and I want it be a parameter that will be provided to stored procedureSnowflake supports a single DATE data type for storing dates (with no time elements). Trying to get the "native"/NTZ time from a timestampntz field. Excluding only weekends doesn't work for business purposes. 2. TABLES WHERE. The syntax for using the DATEDIFF function in Snowflake and Amazon Redshift, and Databricks looks like the following: datediff (< date part >, < start date / time >, < end date / time >) A note on Databricks: Databricks additionally supports a separate DATEDIFF function that takes only two arguments: a start date and an end date. I'm guessing that Trino also looks at the difference in hours between the two timestamps to approximate the result down if it's less than 24 hours. functions. Note that setting a negative offset has the same effect as using the LEAD function. My Snowflake SQL Query : SELECT O. This topic describes how to use the different types of window functions supported by Snowflake, including: General window functions. The expression to be returned based on the specified offset. What about bank holidays? The typical way this is handled is to create a Calendar table with one row per day for the next N years, with fields for year, month, week number, day etc and flags that determine whether it's a working day, holiday, weekend etc. Please find the sample table contents below. I usually get the error: Generator ROWCOUNT must be constant. The syntax for DATEDIFF is pretty straightforward: DATEDIFF (datepart, startdate, enddate) Let’s explore the parameters used here: datepart: The unit of time you want to use for the calculation, like year, quarter, month, day, or even smaller units like hour, minute, or second. DATEDIFF (DAY/WEEK,. Answer. Alias for DATEADD. 問題は、datediff関数が年を時間単位として計算していることです。 「年齢の計算だから年を時間単位にするはずだろう」という声が聞こえてきそうですが、注目すべきは時間単位が年であるとどんな問題が起こるかです！ 次の表を見てみましょう。functions. TIMEADD. 'Datetime' is filetype DateTime in snowflake, but in SQL, it's just a date MM-DD-YYYY, so there is the 6:00 added to turn it into a datetime. Alias for DATEDIFF. So if you run that code in April (today) it's get 30th April. Input: DAY ----- 2022-06-09 2022-04-04 Output DAY_MONTH -----. Currently I am only returning 1. Create an intermediate temporary table, e. The function supports units of years, quarters, months, weeks, days, hours, minutes, seconds, milliseconds, microseconds, and nanoseconds. timestamp_expr. I've got a rather simple custom SQL query driving a workbook, but I would like to speed it up by adding a WHERE clause to it that only looks at transactions with a complete date in the past 366 days. Date_Time, Stack Overflow. MSSQL on the other hand does an implicit cast of '0' to DATE '1900-01-01' and returns the result in the requested date part. In SQL Server I can do this using recursive SQL but looks like that functionality is not available in Snowflake. CREATE TABLE t (id int, creation_date VARCHAR (19. 2 days, but Snowflake will produce 1 because 2 is 1 more than 1. datediff. Then you can run a fairly simple query: select t. In the following example, we compare tables between PostgreSQL and Snowflake using the hashdiff algorithm:I have a use case that I need to run a sql code snippet in a stored procedure, I saw this post and I didn't see how I can utilize my code using the suggested solution. If either the input_expr or the scale_expr is NULL, the result is NULL. If no input row lies exactly at the desired percentile, the result is calculated using linear interpolation of the two nearest input values. The number of rows backward from the current row from which to obtain a value. 33%. value. Supported date and. Here's something slightly different from what the o. To calculate the difference between two timestamps, convert them to unix timestamps then subtract: Master date and time queries in Snowflake with our comprehensive guide. The "DATEDIFF(timeUnit, datetime, datetime2)" function (Microsoft SQL Server, Redshift, Snowflake). schemaname. I guess first I need to find "min_data" for value, then "next_date" and calculate "DATEDIFF". Use the DATEDIFF() function to retrieve the number of days between two dates in a MySQL database. approx_percentile_combine. approx_percentile. For numeric string arguments that are not constants, if NUMBER (18,5) is not sufficient to represent the numeric value, you should cast the argument to a type that can. , DATEDIFF and DATEADD). e. datediff (part: str, col1: ColumnOrName, col2: ColumnOrName) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. So, in your code where you have, for example sum(iff(iscode=1,1,0)), you. So I got help to get started on this and it runs well. Simple right? The only thing is that difference in years is duplicated here. snowpark. October 10, 2023. I am not able to find the right solution for this. Created_Date)/86400 >=8. I'm having trouble getting it to run in snowflake. unable to understand the dateadd function in SQL. Snowflake. * from (select t. Hi @JustineMit - if an answer helps you, please upvote and/or accept it. The date functions in Snowflake are same or slightly different compared to other RDBMS. I am trying to perform the below mentioned code from Microsoft SQL server to snowflake however, am successful so far. Stack Overflow. Hour of the specified day. Krusader. So, the following snippet returns 119 ( 6 = 7th January 1990 ) SELECT DATEDIFF (year, '1900/01/07', '2019/05/15'); Share. I'm trying to calculate an age value for our users based on their birthday, which one would expect to be a simple enough operation. Dec 15, 2022 at 22:20. DATEDIFF () function is used to subtract two dates, times, or timestamps based on the date or time part requested. If you use TRY_TO_DATE and the value "fails to parse" you will get null, thus you can feed the result of that TRY into the DATEDIFF or you can use an inline IFF you skip that thus something like: IFF(TRY_TO_DATE(before_datetime) IS NOT NULL AND TRY_TO_DATE(after_datetime) IS NOT NULL, DATEDIFF('days', before_datetime, after_datetime), 0) AS. Data Superheroes. This uses the row_number window function along with dateadd and generator to increment from a. The collation of the result of the function is the highest-precedence collation of the inputs. 이 함수는 연도, 분기, 월, 주, 일, 시간, 분, 초, 밀리초, 마이크로초, 나노초 단위를 지원합니다. datediff (part: str, col1: ColumnOrName, col2: ColumnOrName) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. 1239') returns 1. I am trying to get the same output in Snowflake, but cant figure out how to return a float. snowflake. 1. Para ambos DATEDIFF e sinal de menos: Os valores de saída podem ser negativos, por exemplo, -12 dias. For example, you can use interval data type functions to add years, months, days, hours, etc to the timestamp variables. Min/Max of a group. I have a table that contains all checkin dates for all users for a business. 2 Answers. The difference between TZ and LTZ comes from the offset set in the database, meaning that even if the displayed offset is +0019 (19 minutes), the difference is <60 seconds. 1239') は1. An aggregate function always returns exactly one row, even when the input contains zero rows. For example, you can use interval data type functions to add years, months, days, hours, etc to the timestamp variables. You can use the SWITCH statement form of CASE thus you just need to branch the options you want, and matching one will be used. The Fix: Instead, you must use the DATEDIFF or TIMESTAMPDIFF function. BirthDate) we subtract 1 day from the current date as the other day is '1/1/1900', which adds one day to the interval. Using Window Functions. Snowflake Summit is coming home to San Francisco. Follow asked Feb 4, 2022 at 0:30. TIMESTAMPDIFF. firstdate))) OVER. snowpark. If you want the difference, then use datediff () or timestampdiff (). firstdate)), AVG(AVG(DATEDIFF('days',dex. Invalid function type [TIMEDIFF] for window function. (Most window functions require at least one column or. 1 to be 0. An aggregate function takes multiple rows (actually, zero, one, or more rows) as input and produces a single output. Snowflake supports using string constants to specify fixed date, time, or timestamp values. datediff (part: str, col1: ColumnOrName, col2: ColumnOrName) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. A date to be converted into a timestamp. 5401041667. Collation Details¶. e. approx_percentile_estimate. To calculate the difference between two timestamps, convert them to unix timestamps then subtract: Master date and time queries in Snowflake with our comprehensive guide. 300'); You can truncate the milliseconds and leave the same data type, you will still see zeros but not different values:First. Window functions that calculate rank (e. By submitting this form, I understand Snowflake will process my personal information in. Image file. A common business problem is calculating the number of working days or hours between two timestamps. example, if start_date and end_date differed by 59 seconds, then DATEDIFF(MINUTE, start_date, end_date) / 60. I tried to define the correct start date with a SQL CASE before i start the AVG(DATEDIFF). highest, second-highest, etc. timezone 매개 변수는 미국/시카고 시간으로 설정됩니다. The spark datediff is different from snowflake datediff this can imply some manual changes. Arguments. For seconds: DATEDIFF (second, LAG (ACTION_DATE) OVER (PARTITION BY users ORDER BY ACTION_DATE), ACTION_DATE ) AS DIFF_SECONDS. snowflake. here is one. If so, 20 business days is exactly 4 weeks, which is exactly 28 days. If the input data type is DATE, and the date_or_time_part is hours or. functions. Current Date/Timestamp Functions. String constants must always be enclosed between delimiter characters. Are you trying to get the first day of the previous month? If so, try this DATEADD( month, -1 , date_trunc('month', current_date()) ) DATEDIFF의 경우: date_or_time_expr1 및 date_or_time_expr2 는 날짜, 시간 또는 타임스탬프일 수 있습니다. Use the Snowpark API to call system-defined functions, UDFs, and stored procedures. 2. 小数秒は丸められません。. working_day_start_timestamp else t. I want to run the same code again with different parameters and want. sql. Extracts the corresponding date part from a date or timestamp. Gordon's answer is useful, but beware -- seq4() is not guaranteed to produce sequential numbers. DATEDIFF ( date_or_time_part, date_or_time_expr1, date_or_time_expr2) Calculates the difference between two date, time, or timestamp expressions based on the date or time part. MSSQL on the other hand does an implicit cast of '0' to DATE '1900-01-01' and returns the result in the requested date part. help on ways to cast the row_count argument for generator() as integer using datediff result . The reason I like to do it this way, is because its flexible enough that I can add weekly, hourly, or monthly intervals between the dates and reuse the code. SELECT DATEADD(WEEK, DATEDIFF(WEEK,0,GETDATE()),-3) But based on my reading and some SQL Fiddle, it seems to output the start of "this week" minus 3 days. Here is an example Here is an exampleSnowflake bills for this idle time, and therefore it can be helpful to "charge back" this cost to the query. ORDER_DATE, CASE WHEN ORDER_DATE IS. array_aggSnowflake is imho for doing complex queries that don't run elsewhere, so why would you run them the worst way, just to "hide" some complexity that is not that complex. Is there a way around this, or a way to predetermine which date is null up front? (psudocode)functions. Need to break down a date field "DAY" to monthly and weekly wise in snowflake. array_aggThe Snowpark library provides an intuitive library for querying and processing data at scale in Snowflake. If { Ignore | Respect } NULL is not specified then default will be Respect Nulls. If you then apply a further DATEADD () operation to that date, as in the. snowflake-cloud-data-platform; Share. Invalid function type [DATEDIFF] for window function. For the 2-argument version: The source_timestamp argument is considered to include the time zone. How to get difference betwen these below two dates in snowflake. later_date, p. The function will always. datediff. Accepts relevant date and time parts (see next section for details). *, min (date) over (partition by cardid) as min_date from t ) t where legit = 0 and date < min_date + interval '10 day. : create temp table dummy_1 (days int) as select datediff ('day', '2018-07-20', '2018-07-27'); 2. functions. To sum up, depending on requirements: DEFAULT DATE 'YYYY-MM-DD' or if it has to be a current date DEFAULT. Para DATEDIFF: date_or_time_expr1 e date_or_time_expr2 podem ser uma data, hora ou carimbo de data/hora. where (DateDiff (d, FilteredPhoneCall. snowpark. This function takes two arguments: The end date. date_or_time_part 은. To run a stored procedure inside a transaction, you. This should be an integer. > Snowflake Forums. The function supports units of years, quarters, months, weeks, days, hours, minutes, seconds, milliseconds, microseconds, and nanoseconds. date_from, evnt. datediff¶ snowflake. たとえば、 DATEDIFF (milliseconds, '00:00:00', '00:00:01. For example, DATEDIFF(milliseconds, '00:00:00', '00:00:01. Invalid function type [TIMEDIFF] for window function. functions. datediff (part: str, col1: ColumnOrName, col2: ColumnOrName) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. 이 함수는 연도, 분기, 월, 주, 일, 시간, 분, 초, 밀리초, 마이크로초, 나노초 단위를 지원합니다. 3. For DATEDIFF: date_or_time_expr1 and date_or_time_expr2 can be a date, time, or timestamp. approx_percentile_combine. functions. For example, -0. I use the following where condition as 0 to select the value on today's date. You can also use these to calculate age. functions. functions. Snowflake DATEDIFF function returns the difference between 2 dates thus it doesn't accept NUMBER as an argument in place of a date. Returns the number of days from startDate to endDate. Truncation. datediff (part: str, col1: Union [Column, str], col2: Union [Column, str]) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested, and returns result of col2 - col1 based on the requested date or time part. It specifies the offset from which the substring starts. There are certain use case scenarios when it is recommended to use the CURRENT_DATE function within the Snowflake cloud data warehouse which are as follows: You want to match the current date with column value to get the required output. Commonly used datepart units include month or second. No exemplo a seguir, o parâmetro TIMESTAMP_TYPE_MAPPING é definido como TIMESTAMP_LTZ (fuso horário local). Learn how to use the DATEDIFF function in Snowflake to calculate the difference between two date, time, or timestamp expressions based on the date or time part requested. array_aggLearn date and time functions in SQLJOIN A USER GROUP CHAPTER Located in cities around the world, our user groups bring together data professionals to connect, share ideas and innovate together. For DATEDIFF: date_or_time_expr1 and date_or_time_expr2 can be a date, time, or timestamp. When calculating it, only from 9am till 17pm and weekdays are needed to be accounted. snowflake. This gist creates a function in Postgres that implements the DATEDIFF function found in Snowflake, BigQuery, and Redshift. Hi @SQL Baby , Last Day of previous month：. Hi @JustineMit - if an answer helps you, please upvote and/or accept it. SET MY_VARIABLE=10; SET MY_VARIABLE='example'; Multiple variables can be initialized in the same statement, thereby reducing the number. For timestamp_expr, the time portion of the input value. Returns the current timestamp for the system, but in the UTC time zone. If the data type is TIME, then the date_or_time_part must be in units of hours or smaller, not days or bigger. CREATED_AT_DATE,dex. If you want to mimic hive logic in snowflake, you should use below code -. 有効な文字列を日付、時刻、またはタイムスタンプへの変換¶. It can be one of the following formats: Year:. 000. Then you can run a fairly simple query: select t. SELECT datediff(MS, '2013-06-30 23:59:59. dates from the DATEDIFF() 1. Establish a session with which you interact with the Snowflake database. PERCENTILE_CONT¶. 小数秒は丸められません。. That means you could get a series of disparate dates instead of the desired result. functions. datediff ( part : str , col1 : Union [ Column , str ] , col2 : Union [ Column , str ] ) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested, and returns result of col2 - col1 based on the. Thanks for help . The collation specifications of all input arguments must be compatible. array_aggSyntax: DATEDIFF(date_part, date1, date2, [start_of_week]) Output: Integer: Definition: Returns the difference between <date1> and <date2n> expressed in units of <date_part>. 9 and 2. Datediff didn't work: DATEDIFF(hour,2,TO_DATE(substr(p. Thanks! Expand Post. SUBSTR ('abc', 1, 1) returns ‘a’, not. Die Funktion gibt das Ergebnis der Subtraktion des zweiten Arguments vom dritten Argument zurück. 이 함수는 연도, 분기, 월, 주, 일, 시간, 분, 초, 밀리초, 마이크로초, 나노초 단위를 지원합니다. – string_expr or timestamp_expr or variant_expr or integer. To comply with ANSI standards, this function can be called without parentheses. The. createdon, GETDATE ()) = 0 or DateDiff (d, FilteredPhoneCall. For DATEDIFF: date_or_time_expr1 and date_or_time_expr2 can be a date, time, or timestamp. 5 is rounded to -1. For example, if we want to get the name ‘John’ from the name ‘John Rose’, then we can make use of this function as: substring (‘John Rose’,0,4). id , sum (datediff (‘second’, -- calculate the max of the two start time (case when t. HOWEVER, if the clicked date is not found (meaning it is set to: '2999-12-31') then take the deadline date - claimed date. I usually us datediff(dd, l. 1 Answer. you ca also use LAG analytical function to get the desired results as : Suppose below is your input table: id account_number account_date 1 1001 9/10/2011 2 2001 9/1/2011 3 2001 9/3/2011 4 1001 9/12/2011 5 3001 9/18/2011 6 1001 9/20/2011 select id,account_number,account_date, datediff(day,lag(account_date,1) over (partition by. functions. Get the Average of a Datediff function using a partition by in Snowflake. Supported date and time parts. You can even find the number of hours, minutes, seconds, and so on in terms of details in. Applies to: Databricks SQL preview Databricks Runtime 11. If the variant contains a date, the date value is preserved as is. 3. Make sure that the data type of each column is consistent across the rows from different sources. I have attached the query with this comment. Recent Snowflake feature improvements mean that it’s becoming easier to generate monitoring and administrative email notifications from within the platform. I want the end result to be a date. approx_percentile_estimate. looks like you need to create a procedure that loops MONTHS_BETWEEN times and use if/else conditions to check if you hit the last month and functions DATEDIFF and LAST_DAY to calculate number of days. SELECT DATEDIFF(MINUTE, LAST_ALTERED, CURRENT_TIMESTAMP()) AS MINUTES_SINCE_LAST_UPDATE FROM MONITORING. We would like to show you a description here but the site won’t allow us. Join us at Snowflake Summit 2024 to explore all the cutting-edge innovation the Data Cloud has to offer. This code: DATEADD (mm, 1 + DATEDIFF (mm, 0, GETDATE ()), -1) In the original question is another way of obtaining "the last day of the current month" 1 - and gets the same rounding behaviour described above. In this article: Syntax. snowpark. DATEDIFF. When specified as a time, then the DATEDIFF function sets the missing date part to 1900-01-01. Share. Databricks vs Snowflake: Performance. Snowflake supports a single DATE data type for storing dates (with no time elements). DATEDIFF on several events for specific value. 小数秒は丸められません。たとえば、 DATEDIFF(milliseconds, '00:00:00', '00:00:01. I can't quite figure out how to add this to the actual query instead of using a relative filter after all data. I have used the code contained below to create date and time scaffolds for several clients for various reasons, such as populating records between the “CreateDate” and “CloseDate” of a data point. Add a comment. functions. Below is SQL Server:YEAR* / DAY* / WEEK* / MONTH / QUARTER¶. The number of dateparts separating two date/time instances is too large You can use following method which is overflow-safe and gives you a float result:DATEDIFF on several events for specific value - Part 2. Download file Snowflake Datediff ignores timezones Download. When date_or_time_part is week (or any of its variations), the output is controlled by the WEEK_START session parameter. For DATE and TIMESTAMP data,. Le signe moins ( -) peut également être utilisé pour soustraire des dates. array_aggYou can subtract days from a date in Snowflake using the DATEADD function. 2. Given the basic example,. CREATE OR REPLACE FUNCTION fn_get_timestamps_in_range (grain VARCHAR, start_tsmp TIMESTAMP_TZ, end_tsmp TIMESTAMP_TZ) RETURNS. start <= w. With this you can calculate the. Compare data tables between databases. In my experience,. You should add another column to indicate the type of count you're calculating, but you can accomplish this with datediff,last_day, and date_trunc(to get first of month). checkin_date, '2018-08-01') <= 90, 1, 0)) as visits_past_90_days, from user_checkin as uc where uc. SnowflakeのDATEDIFF関数では、指定している単位（今回は「DAY」）の数値のズレを計算するため、BQとは異なる結果が出力される。 そのため、例えば、5月8日の23時39分20秒と日付が変わった瞬間の時刻の差分を計算すると、実際には20分程度しかたっていないにも. 1. A window function is any function that operates over a window of rows. select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. Many applications use date functions to manipulate the date and time data types. Why DATEDIFF() function in Snowflake works differently while getting date difference in weeks. What is the best reusable way to calculate the total number of seconds that occurred on business days between two datetime values (ignoring weekends and federal holidays)? Here is a brief and simplified extract of my current dataset: All my users currently have a start time and end time for various actions they complete. approx_count_distinct. In SQL Server, you can convert this to a floating point date serial number (days since 1900-01-01): select convert (float, my_timestamp_field) as float_serial_number. Fractional seconds are not rounded. expr. -2. date '2010-09-14' time '10:03:56' timestamp '2009-09-15 10:59:43'. たとえば、 DATEDIFF (milliseconds, '00:00:00', '00:00:01. However then. functions. snowflake. In certain cases, such as string-based comparisons or when a result depends on a different timestamp format than is set in the session parameters, we recommend explicitly converting. There are 3 different timestamp types in Snowflake: TIMESTAMP_NTZ. Grants_To_Users. snowpark. g. For source_tz and target_tz, you can specify a time zone name or a. snowpark. Accepts relevant date and time parts (see next section for details). So this is really two parts, to know what year-quarter something is with respect to an offset, you just need to subtract the offset month, from the date you have and then year and quarter the adjusted date. snowpark. 'a string') and string arguments that are not constants to the type NUMBER (18,5). I'm guessing that Trino also looks at the difference in hours between the two timestamps to approximate the result down if it's less than 24 hours. In SQL Server, I would create date ranges so I wouldn't have to always change dates in all my where clauses. One way to do this is by creating a working hours table. 0. (SELECT DATEDIFF(second ,CREATED. The string must start with the first two characters (case-insensitive) of the day name: su (Sunday) mo (Monday) tu (Tuesday) we (Wednesday) th (Thursday)Join our community of data professionals to learn, connect, share and innovate together. Setting variables in snowflake. Get the field type for each column in a table. approx_percentile_estimate. Arguments¶ condition# In the first form of CASE, each condition is an expression that should evaluate to a BOOLEAN value (True, False, or NULL). (Snowflake) is much more elegant,. I am looking to understand what the average amount of days between transactions is for each of the customers in my database using Snowflake. Concatenation operator: While we were running & repointing our loads into Snowflake we discovered a important difference in how Oracle vs Snowflake concatenation works. The DATEDIFF function will still work, but you'll want to make sure the input parameters are correct. functions. functions. How do I work with variables in snowflake. I am new to Snowflake, I need to get info on loans 90 day or more delinquent. 🔀 To compare data between databases, install data-diff with specific database adapters, e. How do I generate a gapless date range between my start and end dates? Thank you! snowflake-cloud-data-platform Share Improve this question Follow edited Jun 28, 2022 at 16:35 asked Jun 28, 2022 at 16:20 Josh Fortunatus 25 4 Learn how to use the DATEDIFF function in Snowflake to calculate the difference between two date, time, or timestamp expressions based on the date or time part requested. By default, half-points are rounded away from zero for decimals. datediff (part: str, col1: ColumnOrName, col2: ColumnOrName) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. DATETIME. select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. Can anybody help how can we pass dynamic dates in snowflake View/Table. functions. Typically, if the input contained zero. Unfortunately, the naive approach with the DATEDIFF() function doesn't quite cut it here - using DATEDIFF('year', birthday, current_date) nets the difference between the current year and the birthday year, which could be a very inaccurate representation of the. What is the best reusable way to calculate the total number of seconds that occurred on business days between two datetime values (ignoring weekends and federal holidays)?Split time duration between start_time and endtime by minute In Snowflake 1 Snowflake SQL: trying to calculate time difference between subsets of subsequent rows2. timestamp "2022-01-02T12:30:30. snowflake. select datediff (second, CURRENT_TIMESTAMP, fs.